What is the integral from 0 to 1 of (e^{-x^2}) ?

The integral from 0 to 1 of (e^{-x^2}) is 0.74682…

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integral from 0 to 1 of (e^{-x^2})

\int_{0}^{1} (e^{- x^{2}}) d x

0.74682 \dots

Solution steps

\int_{0}^{1} e^{- x^{2}} d x

Use the nonelementary integral:

\int e^{- x^{2}} d x = \frac{π}{2} erf (x)

= [\frac{π}{2} erf (x)]_{0}^{1}

Compute the boundaries:

0.74682 \dots

= 0.74682 \dots

\int a cos (wt) d t

\frac{d}{d x} ((x - 3)^{3} (x + 4) (x^{2} + 1))

y = x - x^{3}

\int (cos (x))^{5} d x

\frac{\partial}{\partial y} (\frac{x - y}{x + z})

What is the integral from 0 to 1 of (e^{-x^2}) ?
The integral from 0 to 1 of (e^{-x^2}) is 0.74682…