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Popular >

(2/t)^'

Solution

(\frac{2}{t})^{^{'}}

Solution

- \frac{2}{t ^{2}}

Solution steps

(\frac{2}{t})^{'}

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 (\frac{1}{t})^{^{'}}

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 2 (t^{- 1})^{^{'}}

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 (- 1 \cdot t^{- 1 - 1})

Simplify

2 (- 1 \cdot t^{- 1 - 1}) : - \frac{2}{t ^{2}}

= - \frac{2}{t ^{2}}

Popular Examples

maclaurin 1/(5x+7)maclaurin

\frac{1}{5 x + 7}

y^{^{'}} = 2 y - y^{3}

integral of 1/(x^2-3)

\int \frac{1}{x ^{2} - 3} d x

y^{^{'}} = x + 3 y

derivative of (1-2x)^{1/2}derivative of

(1 - 2 x)^{\frac{1}{2}}

Frequently Asked Questions (FAQ)

What is the (2/t)^' ?
The (2/t)^' is -2/(t^2)
What is the first (2/t)^' ?
The first (2/t)^' is -2/(t^2)