What is the derivative of f(2)=x^3-2x ?

The derivative of f(2)=x^3-2x is 3x^2-2

What is the first derivative of f(2)=x^3-2x ?

The first derivative of f(2)=x^3-2x is 3x^2-2

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derivative of

f (2) = x^{3} - 2 x

3 x^{2} - 2

Solution steps

\frac{d}{d x} (x^{3} - 2 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (2 x)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (2 x) = 2

= 3 x^{2} - 2

x \to 2 - lim (x + 7)

\frac{\partial}{\partial x} (20 - (3 x^{2} + y^{2}))

\frac{d}{d x} (\frac{5 x}{2})

\frac{\partial}{\partial y} (- e^{x} ln (y))

y = sin (sin (x)), (π, 0)

What is the derivative of f(2)=x^3-2x ?
The derivative of f(2)=x^3-2x is 3x^2-2
What is the first derivative of f(2)=x^3-2x ?
The first derivative of f(2)=x^3-2x is 3x^2-2