What is (\partial)/(\partial y)(2xy+y) ?

The answer to (\partial)/(\partial y)(2xy+y) is 2x+1

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(\partial)/(\partial y)(2xy+y)

\frac{\partial}{\partial y} (2 x y + y)

2 x + 1

Solution steps

\frac{\partial}{\partial y} (2 x y + y)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (2 x y) + \frac{\partial}{\partial y} (y)

\frac{\partial}{\partial y} (2 x y) = 2 x

\frac{\partial}{\partial y} (y) = 1

= 2 x + 1

e^{2}

f (x) = - x^{2} + 3 x

\frac{d}{d x} (c x^{- 1})

\int x^{\frac{1}{a}} d x

f (x) = 3 x^{3} - x^{2} + 5, (2, 25)

What is (\partial)/(\partial y)(2xy+y) ?
The answer to (\partial)/(\partial y)(2xy+y) is 2x+1