What is inverse oflaplace 1/((s+5)) ?

The answer to inverse oflaplace 1/((s+5)) is e^{-5t}

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inverse oflaplace 1/((s+5))

inverse laplace

\frac{1}{( s + 5 )}

e^{- 5 t}

Solution steps

L^{- 1} {\frac{1}{( s + 5 )}}

Use Inverse Laplace Transform table:

L^{- 1} {\frac{1}{s - a}} = e^{a t}

L^{- 1} {\frac{1}{s + 5}} = e^{- 5 t}

= e^{- 5 t}

\frac{1}{5 s - 2}

\int \frac{x ^{2}}{2 x} d x

\int c^{x} d x

x \to - 2 lim (4 x^{2} + 3 x - 1)

\int (6 x^{2} - 3 x + 5) d x

What is inverse oflaplace 1/((s+5)) ?
The answer to inverse oflaplace 1/((s+5)) is e^{-5t}