What is the derivative of f(x)=(2x^3+4x+1) ?

The derivative of f(x)=(2x^3+4x+1) is 6x^2+4

What is the first derivative of f(x)=(2x^3+4x+1) ?

The first derivative of f(x)=(2x^3+4x+1) is 6x^2+4

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derivative of

f (x) = (2 x^{3} + 4 x + 1)

6 x^{2} + 4

Solution steps

\frac{d}{d x} ((2 x^{3} + 4 x + 1))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{3}) + \frac{d}{d x} (4 x) + \frac{d}{d x} (1)

\frac{d}{d x} (2 x^{3}) = 6 x^{2}

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (1) = 0

= 6 x^{2} + 4 + 0

Simplify

= 6 x^{2} + 4

\int (4 + 4 tan^{2} (v)) d v

(sin (\frac{x}{2}))^{^{'}}

\frac{\partial}{\partial x} (x y^{2} + y e^{x^{2}} + 5)

\frac{d y}{d x} + 2 x y = 2 x^{3}, y (0) = 2

\int 1 d ln (x) d x

What is the derivative of f(x)=(2x^3+4x+1) ?
The derivative of f(x)=(2x^3+4x+1) is 6x^2+4
What is the first derivative of f(x)=(2x^3+4x+1) ?
The first derivative of f(x)=(2x^3+4x+1) is 6x^2+4