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Popular >

derivative of y=ln(t^2)-arctan(t/3)

Solution

derivative of

y = ln (t^{2}) - arctan (\frac{t}{3})

Solution

\frac{2}{t} - \frac{3}{t ^{2} + 9}

Solution steps

\frac{d}{d t} (ln (t^{2}) - arctan (\frac{t}{3}))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (ln (t^{2})) - \frac{d}{d t} (arctan (\frac{t}{3}))

\frac{d}{d t} (ln (t^{2})) = \frac{2}{t}

\frac{d}{d t} (arctan (\frac{t}{3})) = \frac{3}{t ^{2} + 9}

= \frac{2}{t} - \frac{3}{t ^{2} + 9}

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- \frac{2}{s ^{3} ( s - 3 )}

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\int_{0}^{N} e^{- s t} e^{- 2 t} d t

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Frequently Asked Questions (FAQ)

What is the derivative of y=ln(t^2)-arctan(t/3) ?
The derivative of y=ln(t^2)-arctan(t/3) is 2/t-3/(t^2+9)
What is the first derivative of y=ln(t^2)-arctan(t/3) ?
The first derivative of y=ln(t^2)-arctan(t/3) is 2/t-3/(t^2+9)