What is the solution for y^'+10x^4y=50x^9e^{3x^5} ?

The solution for y^'+10x^4y=50x^9e^{3x^5} is y=2e^{3x^5}x^5-(2e^{3x^5})/5+(c_{1})/(e^{2x^5)}

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y^'+10x^4y=50x^9e^{3x^5}

y^{^{'}} + 10 x^{4} y = 50 x^{9} e^{3 x^{5}}

y = 2 e^{3 x^{5}} x^{5} - \frac{2 e ^{3 x^{5}}}{5} + \frac{c _{1}}{e ^{2 x^{5}}}

Solution steps

y^{'} (x) + 10 x^{4} y = 50 x^{9} e^{3 x^{5}}

Solve linear ODE:

y = 2 e^{3 x^{5}} x^{5} - \frac{2 e ^{3 x^{5}}}{5} + \frac{c _{1}}{e ^{2 x^{5}}}

y = 2 e^{3 x^{5}} x^{5} - \frac{2 e ^{3 x^{5}}}{5} + \frac{c _{1}}{e ^{2 x^{5}}}

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What is the solution for y^'+10x^4y=50x^9e^{3x^5} ?
The solution for y^'+10x^4y=50x^9e^{3x^5} is y=2e^{3x^5}x^5-(2e^{3x^5})/5+(c_{1})/(e^{2x^5)}