What is the derivative of f(t)=sin^2(t) ?

The derivative of f(t)=sin^2(t) is sin(2t)

What is the first derivative of f(t)=sin^2(t) ?

The first derivative of f(t)=sin^2(t) is sin(2t)

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derivative of

f (t) = sin^{2} (t)

sin (2 t)

Solution steps

\frac{d}{d t} (sin^{2} (t))

Apply the chain rule:

2 sin (t) \frac{d}{d t} (sin (t))

= 2 sin (t) \frac{d}{d t} (sin (t))

\frac{d}{d t} (sin (t)) = cos (t)

= 2 sin (t) cos (t)

Use the Double Angle identity:

2 sin (x) cos (x) = sin (2 x)

= sin (2 t)

\frac{x ^{3}}{2}

\int 8 d x

\int 50 x^{9} e^{5 x^{5}} d x

\frac{d}{d x} (\frac{x ^{2}}{sin ^{2} ( x )})

x \to 3 - lim (\frac{∣ 3 - x ∣}{x - 3})

What is the derivative of f(t)=sin^2(t) ?
The derivative of f(t)=sin^2(t) is sin(2t)
What is the first derivative of f(t)=sin^2(t) ?
The first derivative of f(t)=sin^2(t) is sin(2t)