What is the integral of 6x^5-8x^4-9x^2 ?

The integral of 6x^5-8x^4-9x^2 is x^6-(8x^5)/5-3x^3+C

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integral of 6x^5-8x^4-9x^2

\int 6 x^{5} - 8 x^{4} - 9 x^{2} d x

x^{6} - \frac{8 x ^{5}}{5} - 3 x^{3} + C

Solution steps

\int 6 x^{5} - 8 x^{4} - 9 x^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 6 x^{5} d x - \int 8 x^{4} d x - \int 9 x^{2} d x

\int 6 x^{5} d x = x^{6}

\int 8 x^{4} d x = \frac{8 x ^{5}}{5}

\int 9 x^{2} d x = 3 x^{3}

= x^{6} - \frac{8 x ^{5}}{5} - 3 x^{3}

Add a constant to the solution

= x^{6} - \frac{8 x ^{5}}{5} - 3 x^{3} + C

y^{^{'}} = 2 t e^{7 y}

\int x e^{- 4 x} d x

f (x) = \frac{- 3}{x ^{4}}

\int_{4}^{69} \frac{1}{x ^{3} - 64} d x

x \to 0 lim (x^{2} + 4)

What is the integral of 6x^5-8x^4-9x^2 ?
The integral of 6x^5-8x^4-9x^2 is x^6-(8x^5)/5-3x^3+C