What is the derivative of 2/(x^2-4) ?

The derivative of 2/(x^2-4) is -(4x)/((x^2-4)^2)

What is the first derivative of 2/(x^2-4) ?

The first derivative of 2/(x^2-4) is -(4x)/((x^2-4)^2)

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\frac{d}{d x} (\frac{2}{x ^{2} - 4})

- \frac{4 x}{( x ^{2} - 4 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{2}{x ^{2} - 4})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (\frac{1}{x ^{2} - 4})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 2 \frac{d}{d x} ((x^{2} - 4)^{- 1})

Apply the chain rule:

- \frac{1}{( x ^{2} - 4 ) ^{2}} \frac{d}{d x} (x^{2} - 4)

= - \frac{1}{( x ^{2} - 4 ) ^{2}} \frac{d}{d x} (x^{2} - 4)

\frac{d}{d x} (x^{2} - 4) = 2 x

= 2 (- \frac{1}{( x ^{2} - 4 ) ^{2}} \cdot 2 x)

Simplify

2 (- \frac{1}{( x ^{2} - 4 ) ^{2}} \cdot 2 x) : - \frac{4 x}{( x ^{2} - 4 ) ^{2}}

= - \frac{4 x}{( x ^{2} - 4 ) ^{2}}

\frac{d}{d x} (e^{x} arcsin (x))

\int_{- 2}^{3} x d x

\int_{0}^{2} (x^{2} - 3 x) d x

\frac{d}{d x} (\frac{x ^{2} - 7 x + 10}{3 x ^{2} - 15 x})

f (x) = \frac{2 x + 5}{5 x - 1}, at x = - 1

What is the derivative of 2/(x^2-4) ?
The derivative of 2/(x^2-4) is -(4x)/((x^2-4)^2)
What is the first derivative of 2/(x^2-4) ?
The first derivative of 2/(x^2-4) is -(4x)/((x^2-4)^2)