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Popular Calculus >

derivative of sqrt(8x^2+2x-3)

Solution

\frac{d}{d x} (8 x^{2} + 2 x - 3)

Solution

\frac{8 x + 1}{8 x ^{2} + 2 x - 3}

Solution steps

\frac{d}{d x} (8 x^{2} + 2 x - 3)

Apply the chain rule:

\frac{1}{2 8 x ^{2} + 2 x - 3} \frac{d}{d x} (8 x^{2} + 2 x - 3)

= \frac{1}{2 8 x ^{2} + 2 x - 3} \frac{d}{d x} (8 x^{2} + 2 x - 3)

\frac{d}{d x} (8 x^{2} + 2 x - 3) = 16 x + 2

= \frac{1}{2 8 x ^{2} + 2 x - 3} (16 x + 2)

Simplify

\frac{1}{2 8 x ^{2} + 2 x - 3} (16 x + 2) : \frac{8 x + 1}{8 x ^{2} + 2 x - 3}

= \frac{8 x + 1}{8 x ^{2} + 2 x - 3}

Graph

Popular Examples

integral from 1 to 4 of x^2+1/(4x^2)

\int_{1}^{4} x^{2} + \frac{1}{4 x ^{2}} d x

integral of (e^x)/(a+be^x)

\int \frac{e ^{x}}{a + b e ^{x}} d x

(3+x^2)y^'-2xy=0

(3 + x^{2}) y^{^{'}} - 2 x y = 0

integral from 0 to 1 of xsqrt(x^2+1)

\int_{0}^{1} x x^{2} + 1 d x

integral of 1/(7x^7)

\int \frac{1}{7 x ^{7}} d x

Frequently Asked Questions (FAQ)

What is the derivative of sqrt(8x^2+2x-3) ?
The derivative of sqrt(8x^2+2x-3) is (8x+1)/(sqrt(8x^2+2x-3))
What is the first derivative of sqrt(8x^2+2x-3) ?
The first derivative of sqrt(8x^2+2x-3) is (8x+1)/(sqrt(8x^2+2x-3))