What is the solution for (x^2+1)(dy)/(dx)+3x(y-1)=0,y(0)=7 ?

The solution for (x^2+1)(dy)/(dx)+3x(y-1)=0,y(0)=7 is y= 6/((x^2+1)^{3/2)}+1

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(x^2+1)(dy)/(dx)+3x(y-1)=0,y(0)=7

(x^{2} + 1) \frac{d y}{d x} + 3 x (y - 1) = 0, y (0) = 7

y = \frac{6}{( x ^{2} + 1 ) ^{\frac{3}{2}}} + 1

Solution steps

(x^{2} + 1) \frac{d y}{d x} + 3 x (y - 1) = 0

Solve separable ODE:

y = \frac{6}{( x ^{2} + 1 ) ^{\frac{3}{2}}} + 1

y = \frac{6}{( x ^{2} + 1 ) ^{\frac{3}{2}}} + 1

x \to 1 lim (- 2 x + 3)

(t + 2)^{2}

\int 9 x e^{3 x} d x

x \to - 2 - lim (\frac{- 2}{x ^{2} - 4})

\frac{d}{d x} (A sin (2 x) + B cos (2 x))

What is the solution for (x^2+1)(dy)/(dx)+3x(y-1)=0,y(0)=7 ?
The solution for (x^2+1)(dy)/(dx)+3x(y-1)=0,y(0)=7 is y= 6/((x^2+1)^{3/2)}+1