What is the tangent of f(x)=5x^{3/2}-2x,(1,3) ?

The tangent of f(x)=5x^{3/2}-2x,(1,3) is y= 11/2 x-5/2

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tangent of f(x)=5x^{3/2}-2x,(1,3)

tangent of

f (x) = 5 x^{\frac{3}{2}} - 2 x, (1, 3)

y = \frac{11}{2} x - \frac{5}{2}

Solution steps

Find the slope of

f (x) = 5 x^{\frac{3}{2}} - 2 x : \frac{df ( x )}{d x} = \frac{15 x ^{\frac{1}{2}}}{2} - 2

Compute the slope of

f (x) = 5 x^{\frac{3}{2}} - 2 x

(1, 3) : m = \frac{11}{2}

Find the line with slope m=

\frac{11}{2}

and passing through

(1, 3) : y = \frac{11}{2} x - \frac{5}{2}

y = \frac{11}{2} x - \frac{5}{2}

n = 0 \sum \infty \frac{0. 5 ^{n}}{n !}

\int 8 x^{\frac{1}{3}} d x

\frac{\partial}{\partial x} (y e^{x} - 3 x - y + 5)

x \to 0 - lim (\frac{x ^{2} - x}{∣ x ∣})

t \to 0 lim (3)

What is the tangent of f(x)=5x^{3/2}-2x,(1,3) ?
The tangent of f(x)=5x^{3/2}-2x,(1,3) is y= 11/2 x-5/2