What is the solution for x((dy)/(dx))+y=e^x,y(1)=2 ?

The solution for x((dy)/(dx))+y=e^x,y(1)=2 is y=(e^x)/x+(2-e)/x

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x((dy)/(dx))+y=e^x,y(1)=2

x (\frac{d y}{d x}) + y = e^{x}, y (1) = 2

y = \frac{e ^{x}}{x} + \frac{2 - e}{x}

Solution steps

x (\frac{d y}{d x}) + y = e^{x}

Solve linear ODE:

y = \frac{e ^{x}}{x} + \frac{2 - e}{x}

y = \frac{e ^{x}}{x} + \frac{2 - e}{x}

\frac{d}{d x} (ln (x^{\frac{1}{3}}))

\frac{d}{d x} (cos (x (1 + sin (x))^{10}))

\frac{d}{d x} (\frac{x - 8}{x ^{2} - 4})

x^{2} + x y - y^{2} = 3, (5, 3)

\frac{1}{s ^{2} - 6 s + 10}

What is the solution for x((dy)/(dx))+y=e^x,y(1)=2 ?
The solution for x((dy)/(dx))+y=e^x,y(1)=2 is y=(e^x)/x+(2-e)/x