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Popular >

integral of 8y^{-5}

Solution

\int 8 y^{- 5} d y

Solution

- \frac{2}{y ^{4}} + C

Solution steps

\int 8 y^{- 5} d y

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 8 \cdot \int y^{- 5} d y

Apply the Power Rule

: - \frac{1}{4 y ^{4}}

= 8 (- \frac{1}{4 y ^{4}})

Simplify

8 (- \frac{1}{4 y ^{4}}) : - \frac{2}{y ^{4}}

= - \frac{2}{y ^{4}}

Add a constant to the solution

= - \frac{2}{y ^{4}} + C

Popular Examples

integral of 4x^3+e^x+C

\int 4 x^{3} + e^{x} + C d x

tangent of f(x)=(6x)/(x^2+1),(-1,-3)tangent of

f (x) = \frac{6 x}{x ^{2} + 1}, (- 1, - 3)

integral of r*e^{-r^2}

\int r \cdot e^{- r^{2}} d r

integral of (sqrt(16-x^2))/x

\int \frac{16 - x ^{2}}{x} d x

integral from-1 to 0 of 8(e^{1/x})/(x^3)

\int_{- 1}^{0} 8 \frac{e ^{\frac{1}{x}}}{x ^{3}} d x

Frequently Asked Questions (FAQ)

What is the integral of 8y^{-5} ?
The integral of 8y^{-5} is -2/(y^4)+C