What is the derivative of (x-2/(x+1)) ?

The derivative of (x-2/(x+1)) is 3/((x+1)^2)

What is the first derivative of (x-2/(x+1)) ?

The first derivative of (x-2/(x+1)) is 3/((x+1)^2)

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\frac{d}{d x} (\frac{x - 2}{x + 1})

\frac{3}{( x + 1 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x - 2}{x + 1})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x - 2 ) ( x + 1 ) - \frac{d}{d x} ( x + 1 ) ( x - 2 )}{( x + 1 ) ^{2}}

\frac{d}{d x} (x - 2) = 1

\frac{d}{d x} (x + 1) = 1

= \frac{1 \cdot ( x + 1 ) - 1 \cdot ( x - 2 )}{( x + 1 ) ^{2}}

Simplify

\frac{1 \cdot ( x + 1 ) - 1 \cdot ( x - 2 )}{( x + 1 ) ^{2}} : \frac{3}{( x + 1 ) ^{2}}

= \frac{3}{( x + 1 ) ^{2}}

y^{\frac{2}{3}}

\int \frac{e ^{x}}{64 - e ^{2 x}} d x

\int sin (π \cdot x) d x

8 x^{7} e^{x} + e^{x} x^{8}

\int (ln (x) + 3) d x

What is the derivative of (x-2/(x+1)) ?
The derivative of (x-2/(x+1)) is 3/((x+1)^2)
What is the first derivative of (x-2/(x+1)) ?
The first derivative of (x-2/(x+1)) is 3/((x+1)^2)