What is the tangent of f(x)= 1/x ,\at x=-2 ?

The tangent of f(x)= 1/x ,\at x=-2 is y=-1/4 x-1

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tangent of f(x)= 1/x ,\at x=-2

tangent of

f (x) = \frac{1}{x}, at x = - 2

y = - \frac{1}{4} x - 1

Solution steps

Find the tangent point:

(- 2, - \frac{1}{2})

Find the slope of

f (x) = \frac{1}{x} : \frac{df ( x )}{d x} = - \frac{1}{x ^{2}}

Compute the slope of

f (x) = \frac{1}{x}

x = - 2 : m = - \frac{1}{4}

Find the line with slope m=

- \frac{1}{4}

and passing through

(- 2, - \frac{1}{2}) : y = - \frac{1}{4} x - 1

y = - \frac{1}{4} x - 1

\frac{d}{d x} (\frac{x ^{3}}{3} + \frac{x ^{2}}{2} - 6 x)

\frac{d}{d x} (2 e^{x^{2}})

\frac{\partial}{\partial x} ((x + y) e^{x})

\int \frac{1}{P} d P

f (t) = 0.1 (400 - 40 t + t^{2})

What is the tangent of f(x)= 1/x ,\at x=-2 ?
The tangent of f(x)= 1/x ,\at x=-2 is y=-1/4 x-1