What is the sum from n=1 to infinity of n^7(1+n^8)^2 ?

The sum from n=1 to infinity of n^7(1+n^8)^2 is diverges

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sum from n=1 to infinity of n^7(1+n^8)^2

n = 1 \sum \infty n^{7} (1 + n^{8})^{2}

diverges

Solution steps

n = 1 \sum \infty n^{7} (1 + n^{8})^{2}

Apply Series Divergence Test:

diverges

= diverges

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What is the sum from n=1 to infinity of n^7(1+n^8)^2 ?
The sum from n=1 to infinity of n^7(1+n^8)^2 is diverges