What is the tangent of f(x)=xsqrt(x),\at x=4 ?

The tangent of f(x)=xsqrt(x),\at x=4 is y=3x-4

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tangent of f(x)=xsqrt(x),\at x=4

tangent of

f (x) = x x, at x = 4

y = 3 x - 4

Solution steps

Find the tangent point:

(4, 8)

Find the slope of

f (x) = x x : \frac{df ( x )}{d x} = \frac{3 x}{2}

Compute the slope of

f (x) = x x

x = 4 : m = 3

Find the line with slope m=

3

and passing through

(4, 8) : y = 3 x - 4

y = 3 x - 4

\int \frac{( e ^{x} )}{e ^{x} ( e ^{x} - 3 )} d x

\int \frac{( x ^{3} )}{x ^{2} + 81} d x

x^{2} sin (x)

\int \frac{arctan ( 3 x )}{1 + 9 x ^{2}} d x

\int_{0}^{π} sin (3 x) sin (5 x) d x

What is the tangent of f(x)=xsqrt(x),\at x=4 ?
The tangent of f(x)=xsqrt(x),\at x=4 is y=3x-4