What is the derivative of f(x)=sin(tan(3x)) ?

The derivative of f(x)=sin(tan(3x)) is cos(tan(3x))sec^2(3x)*3

What is the first derivative of f(x)=sin(tan(3x)) ?

The first derivative of f(x)=sin(tan(3x)) is cos(tan(3x))sec^2(3x)*3

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derivative of

f (x) = sin (tan (3 x))

cos (tan (3 x)) sec^{2} (3 x) \cdot 3

Solution steps

\frac{d}{d x} (sin (tan (3 x)))

Apply the chain rule:

cos (tan (3 x)) \frac{d}{d x} (tan (3 x))

= cos (tan (3 x)) \frac{d}{d x} (tan (3 x))

\frac{d}{d x} (tan (3 x)) = sec^{2} (3 x) \cdot 3

= cos (tan (3 x)) sec^{2} (3 x) \cdot 3

- x^{2} + 2 x + 4, at x = 3

f (x) = \frac{4 x}{x ^{2} + 1}, at x = 1

\int \frac{1}{x x ^{2} - 5} d x

\int (x + \frac{2}{x}) (x - \frac{2}{x}) d x

\int - 14 x d x

What is the derivative of f(x)=sin(tan(3x)) ?
The derivative of f(x)=sin(tan(3x)) is cos(tan(3x))sec^2(3x)*3
What is the first derivative of f(x)=sin(tan(3x)) ?
The first derivative of f(x)=sin(tan(3x)) is cos(tan(3x))sec^2(3x)*3