What is (\partial)/(\partial x)(16x+32y-1600) ?

The answer to (\partial)/(\partial x)(16x+32y-1600) is 16

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(\partial)/(\partial x)(16x+32y-1600)

\frac{\partial}{\partial x} (16 x + 32 y - 1600)

16

Solution steps

\frac{\partial}{\partial x} (16 x + 32 y - 1600)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (16 x) + \frac{\partial}{\partial x} (32 y) - \frac{\partial}{\partial x} (1600)

\frac{\partial}{\partial x} (16 x) = 16

\frac{\partial}{\partial x} (32 y) = 0

\frac{\partial}{\partial x} (1600) = 0

= 16 + 0 - 0

Simplify

= 16

\frac{x}{x + 1}

n = 0 \sum \infty \frac{1}{n ^{3} - n}

\int \frac{1}{x ^{3} - 4 x ^{2} + 3 x} d x

\int 4 x (x^{2} + 5)^{3} d x

h \to 0 lim (x^{2} + 3 x h)

What is (\partial)/(\partial x)(16x+32y-1600) ?
The answer to (\partial)/(\partial x)(16x+32y-1600) is 16