What is the derivative of xe^{2x+1} ?

The derivative of xe^{2x+1} is e^{2x+1}+2e^{2x+1}x

What is the first derivative of xe^{2x+1} ?

The first derivative of xe^{2x+1} is e^{2x+1}+2e^{2x+1}x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (x e^{2 x + 1})

e^{2 x + 1} + 2 e^{2 x + 1} x

Solution steps

\frac{d}{d x} (x e^{2 x + 1})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = e^{2 x + 1}

= \frac{d x}{d x} e^{2 x + 1} + \frac{d}{d x} (e^{2 x + 1}) x

\frac{d x}{d x} = 1

\frac{d}{d x} (e^{2 x + 1}) = e^{2 x + 1} \cdot 2

= 1 \cdot e^{2 x + 1} + e^{2 x + 1} \cdot 2 x

Simplify

= e^{2 x + 1} + 2 e^{2 x + 1} x

n = 1 \sum \infty 2 0^{n} x^{n} n!

\int_{- π}^{2 π} sin^{2} (x) d x

e^{6}

\int \frac{16}{16 - x ^{2}} d x

\frac{2 x + 6}{x + 9}

What is the derivative of xe^{2x+1} ?
The derivative of xe^{2x+1} is e^{2x+1}+2e^{2x+1}x
What is the first derivative of xe^{2x+1} ?
The first derivative of xe^{2x+1} is e^{2x+1}+2e^{2x+1}x