What is area y=-x^2+16,y=0,x=-2,x=3 ?

The answer to area y=-x^2+16,y=0,x=-2,x=3 is 205/3

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area y=-x^2+16,y=0,x=-2,x=3

area

y = - x^{2} + 16, y = 0, x = - 2, x = 3

\frac{205}{3}

Decimal Notation

68.33333 \dots

Solution steps

Apply the area formula:

\int_{- 2}^{3} - x^{2} + 16 d x

Solve

\int_{- 2}^{3} - x^{2} + 16 d x : \frac{205}{3}

The area is:

= \frac{205}{3}

\frac{d y}{d x} = - \frac{3 x ^{2} + 2 y ^{2}}{4 x y}

\int (2 x - 5) (3 x + 1) d x

x \to 0 lim (2 x)

\int \frac{1}{2 + 9 x ^{2}} d x

\frac{d y}{d x} = 9 x

What is area y=-x^2+16,y=0,x=-2,x=3 ?
The answer to area y=-x^2+16,y=0,x=-2,x=3 is 205/3