What is laplacetransform cos(3t)-cos(7t) ?

The answer to laplacetransform cos(3t)-cos(7t) is s/(s^2+9)-s/(s^2+49)

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laplacetransform cos(3t)-cos(7t)

laplace transform

cos (3 t) - cos (7 t)

\frac{s}{s ^{2} + 9} - \frac{s}{s ^{2} + 49}

Solution steps

L {cos (3 t) - cos (7 t)}

Use the linearity property of Laplace Transform:

For functions

f (t), g (t)

and constants

a, b : L {a \cdot f (t) + b \cdot g (t)} = a \cdot L {f (t)} + b \cdot L {g (t)}

= L {cos (3 t)} - L {cos (7 t)}

L {cos (3 t)} : \frac{s}{s ^{2} + 9}

L {cos (7 t)} : \frac{s}{s ^{2} + 49}

= \frac{s}{s ^{2} + 9} - \frac{s}{s ^{2} + 49}

x^{3} + 3

\int (x^{3} - \frac{1}{x ^{3}})^{2} d x

\int x (1 + 2 x^{4}) d x

\frac{\partial}{\partial x} (4 x^{3} y^{2} + 3)

y = ln (2 x + 1)

What is laplacetransform cos(3t)-cos(7t) ?
The answer to laplacetransform cos(3t)-cos(7t) is s/(s^2+9)-s/(s^2+49)