What is the tangent of y= 3/x ,(5, 3/5) ?

The tangent of y= 3/x ,(5, 3/5) is y=-3/25 x+6/5

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tangent of y= 3/x ,(5, 3/5)

tangent of

y = \frac{3}{x}, (5, \frac{3}{5})

y = - \frac{3}{25} x + \frac{6}{5}

Solution steps

Find the slope of

y = \frac{3}{x} : \frac{d y}{d x} = - \frac{3}{x ^{2}}

Compute the slope of

y = \frac{3}{x}

(5, \frac{3}{5}) : m = - \frac{3}{25}

Find the line with slope m=

- \frac{3}{25}

and passing through

(5, \frac{3}{5}) : y = - \frac{3}{25} x + \frac{6}{5}

y = - \frac{3}{25} x + \frac{6}{5}

f (x) = (2 x + 3) (x^{2} + 2 x)

\int_{0}^{5} x e^{- 0.6 x} d x

\frac{d}{d x} (cot (x))

y = \frac{e ^{x}}{x + e ^{x}}

\frac{\partial}{\partial x} (e^{x y} x^{2})

What is the tangent of y= 3/x ,(5, 3/5) ?
The tangent of y= 3/x ,(5, 3/5) is y=-3/25 x+6/5