What is the derivative of f(x)= 3/2 x^3-8/5 x^2 ?

The derivative of f(x)= 3/2 x^3-8/5 x^2 is (9x^2)/2-(16x)/5

What is the first derivative of f(x)= 3/2 x^3-8/5 x^2 ?

The first derivative of f(x)= 3/2 x^3-8/5 x^2 is (9x^2)/2-(16x)/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

f (x) = \frac{3}{2} x^{3} - \frac{8}{5} x^{2}

\frac{9 x ^{2}}{2} - \frac{16 x}{5}

Solution steps

\frac{d}{d x} (\frac{3}{2} x^{3} - \frac{8}{5} x^{2})

Simplify

\frac{3}{2} x^{3} - \frac{8}{5} x^{2} : \frac{3 x ^{3}}{2} - \frac{8 x ^{2}}{5}

= \frac{d}{d x} (\frac{3 x ^{3}}{2} - \frac{8 x ^{2}}{5})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{3 x ^{3}}{2}) - \frac{d}{d x} (\frac{8 x ^{2}}{5})

\frac{d}{d x} (\frac{3 x ^{3}}{2}) = \frac{9 x ^{2}}{2}

\frac{d}{d x} (\frac{8 x ^{2}}{5}) = \frac{16 x}{5}

= \frac{9 x ^{2}}{2} - \frac{16 x}{5}

\int_{0}^{50} \frac{4}{5} x d x

\int_{0}^{1} \frac{9}{1 - x ^{2}} d x

\frac{\partial}{\partial x} (x^{4} - 5 x y + y^{4})

f (x) = \frac{x ^{2} + 4 x + 3}{x}

y^{^{'}} tan^{- 1} (x) - y (1 + x^{2})^{- 1} = 0

What is the derivative of f(x)= 3/2 x^3-8/5 x^2 ?
The derivative of f(x)= 3/2 x^3-8/5 x^2 is (9x^2)/2-(16x)/5
What is the first derivative of f(x)= 3/2 x^3-8/5 x^2 ?
The first derivative of f(x)= 3/2 x^3-8/5 x^2 is (9x^2)/2-(16x)/5