What is the integral from b to 2b of x^3 ?

The integral from b to 2b of x^3 is 4b^4-(b^4)/4

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integral from b to 2b of x^3

\int_{b}^{2 b} x^{3} d x

4 b^{4} - \frac{b ^{4}}{4}

Solution steps

\int_{b}^{2 b} x^{3} d x

Apply the Power Rule

: [\frac{x ^{4}}{4}]_{b}^{2 b}

= [\frac{x ^{4}}{4}]_{b}^{2 b}

Compute the boundaries:

4 b^{4} - \frac{b ^{4}}{4}

= 4 b^{4} - \frac{b ^{4}}{4}

6 + x - x^{2}, 4

\int \frac{( x ^{2} )}{4 - x ^{2}} d x

\int \frac{5}{( x - 2 ) ( x ^{2} - 1 )} d x

\int \frac{e ^{x^{\frac{1}{2}}}}{x ^{\frac{1}{2}}} d x

f (x) = \frac{4}{x}, (5, \frac{4}{5})

What is the integral from b to 2b of x^3 ?
The integral from b to 2b of x^3 is 4b^4-(b^4)/4