What is (\partial)/(\partial x)(xycos(3yz)) ?

The answer to (\partial)/(\partial x)(xycos(3yz)) is ycos(3yz)

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(\partial)/(\partial x)(xycos(3yz))

\frac{\partial}{\partial x} (x y cos (3 yz))

y cos (3 yz)

Solution steps

\frac{\partial}{\partial x} (x y cos (3 yz))

Treat

y, z

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= y cos (3 yz) \frac{\partial}{\partial x} (x)

Apply the common derivative:

\frac{\partial}{\partial x} (x) = 1

= y cos (3 yz) \cdot 1

Simplify

= y cos (3 yz)

\int (1 - cos (\frac{x}{2}))^{2} sin (\frac{x}{2}) d x

\int_{- 1}^{2} (4 - x^{2}) d x

y = lo g_{5} (2) x^{2}

n = 1 \sum \infty 7^{n + 1} x^{n}

\frac{1}{t}

What is (\partial)/(\partial x)(xycos(3yz)) ?
The answer to (\partial)/(\partial x)(xycos(3yz)) is ycos(3yz)