What is the derivative of x^3-7x ?

The derivative of x^3-7x is 3x^2-7

What is the first derivative of x^3-7x ?

The first derivative of x^3-7x is 3x^2-7

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\frac{d}{d x} (x^{3} - 7 x)

3 x^{2} - 7

Solution steps

\frac{d}{d x} (x^{3} - 7 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (7 x)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (7 x) = 7

= 3 x^{2} - 7

\frac{1}{( s ^{2} + 9 )}

\int \frac{x ^{4} - 3 x ^{2} + 5}{x ^{4}} d x

x \to - 2 lim (\frac{x + 2}{2 x})

\int x sin^{2} (x^{2}) d x

\int \frac{e ^{x}}{e ^{2 x} + 4 e ^{x} + 3} d x

What is the derivative of x^3-7x ?
The derivative of x^3-7x is 3x^2-7
What is the first derivative of x^3-7x ?
The first derivative of x^3-7x is 3x^2-7