What is the tangent of 2/(sqrt(x)),\at x=3 ?

The tangent of 2/(sqrt(x)),\at x=3 is y=-1/(3sqrt(3))x+sqrt(3)

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tangent of 2/(sqrt(x)),\at x=3

tangent of

\frac{2}{x}, at x = 3

y = - \frac{1}{3 3} x + 3

Solution steps

Find the tangent point:

(3, \frac{2}{3})

Find the slope of

y = \frac{2}{x} : \frac{d y}{d x} = - \frac{1}{x ^{\frac{3}{2}}}

Compute the slope of

y = \frac{2}{x}

x = 3 : m = - \frac{1}{3 3}

Find the line with slope m=

- \frac{1}{3 3}

and passing through

(3, \frac{2}{3}) : y = - \frac{1}{3 3} x + 3

y = - \frac{1}{3 3} x + 3

\int \frac{2}{2 x + 1} d x

\int (e^{x})^{2} d x

n = 1 \sum \infty 23 (\frac{2}{5})^{n}

\int \frac{e ^{x}}{3 - e ^{2 x}} d x

y (x + 3) + y^{^{'}} = 0

What is the tangent of 2/(sqrt(x)),\at x=3 ?
The tangent of 2/(sqrt(x)),\at x=3 is y=-1/(3sqrt(3))x+sqrt(3)