What is the tangent of f(x)=(4x)/(x+3),\at x=-5 ?

The tangent of f(x)=(4x)/(x+3),\at x=-5 is y=3x+25

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tangent of f(x)=(4x)/(x+3),\at x=-5

tangent of

f (x) = \frac{4 x}{x + 3}, at x = - 5

y = 3 x + 25

Solution steps

Find the tangent point:

(- 5, 10)

Find the slope of

f (x) = \frac{4 x}{x + 3} : \frac{df ( x )}{d x} = \frac{12}{( x + 3 ) ^{2}}

Compute the slope of

f (x) = \frac{4 x}{x + 3}

x = - 5 : m = 3

Find the line with slope m=

3

and passing through

(- 5, 10) : y = 3 x + 25

y = 3 x + 25

x \to 1.7 lim (sin (x))

\int - \frac{19}{x ^{2} + 1} d x

e^{x} + e^{- x}

f (t) = sin (t)

x \to 2 lim (x^{4} + x^{2} - 4)

What is the tangent of f(x)=(4x)/(x+3),\at x=-5 ?
The tangent of f(x)=(4x)/(x+3),\at x=-5 is y=3x+25