What is the derivative of (16)/x ?

The derivative of (16)/x is -(16)/(x^2)

What is the first derivative of (16)/x ?

The first derivative of (16)/x is -(16)/(x^2)

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derivative of

\frac{16}{x}

- \frac{16}{x ^{2}}

Solution steps

\frac{d}{d x} (\frac{16}{x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 16 \frac{d}{d x} (\frac{1}{x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 16 \frac{d}{d x} (x^{- 1})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 16 (- 1 \cdot x^{- 1 - 1})

Simplify

16 (- 1 \cdot x^{- 1 - 1}) : - \frac{16}{x ^{2}}

= - \frac{16}{x ^{2}}

\frac{\partial}{\partial y} (3 x^{2})

\frac{d}{d x} (x^{5} - 5 x)

\int \frac{x ^{2}}{x + 4} d x

(1 + ln (x) + \frac{y}{x}) d x + (1 - ln (x)) d y = 0

\frac{d}{d t} (e^{2 t} \cdot y)

What is the derivative of (16)/x ?
The derivative of (16)/x is -(16)/(x^2)
What is the first derivative of (16)/x ?
The first derivative of (16)/x is -(16)/(x^2)