What is laplacetransform 2(s+2) ?

The answer to laplacetransform 2(s+2) is 2/(s^2)+4/s

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laplacetransform 2(s+2)

laplace transform

2 (s + 2)

\frac{2}{s ^{2}} + \frac{4}{s}

Solution steps

L {2 (s + 2)}

Expand

2 (s + 2) : 2 s + 4

= L {2 s + 4}

Use the linearity property of Laplace Transform:

For functions

f (t), g (t)

and constants

a, b : L {a \cdot f (t) + b \cdot g (t)} = a \cdot L {f (t)} + b \cdot L {g (t)}

= 2 L {s} + L {4}

L {s} : \frac{1}{s ^{2}}

L {4} : \frac{4}{s}

= 2 \cdot \frac{1}{s ^{2}} + \frac{4}{s}

Refine

2 \frac{1}{s ^{2}} + \frac{4}{s} : \frac{2}{s ^{2}} + \frac{4}{s}

= \frac{2}{s ^{2}} + \frac{4}{s}

\int - 3 cos (x) + 4 sec^{2} (x) d x

\frac{\partial}{\partial x} (4 cos (4 x))

\frac{1}{x + 1}

\int (t + 4) e^{t^{2} + 8 t + 1} d t

y^{^{''}} + 8 y^{^{'}} = - 256 cos (8 x)

What is laplacetransform 2(s+2) ?
The answer to laplacetransform 2(s+2) is 2/(s^2)+4/s