What is the d/(dt)(sin(3t)) ?

The d/(dt)(sin(3t)) is cos(3t)*3

What is the first d/(dt)(sin(3t)) ?

The first d/(dt)(sin(3t)) is cos(3t)*3

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\frac{d}{d t} (sin (3 t))

cos (3 t) \cdot 3

Solution steps

\frac{d}{d t} (sin (3 t))

Apply the chain rule:

cos (3 t) \frac{d}{d t} (3 t)

= cos (3 t) \frac{d}{d t} (3 t)

\frac{d}{d t} (3 t) = 3

= cos (3 t) \cdot 3

y = ln (\frac{x}{x ^{2} + 4})

y = \frac{1}{x}, y = 0, x = 1, x = e

\int \frac{5}{( 81 + x ^{2} ) ^{\frac{3}{2}}} d x

\frac{4}{x ^{6}}