What is the derivative of (e^x-e^{-2x}^{1/5}) ?

The derivative of (e^x-e^{-2x}^{1/5}) is (e^x+2e^{-2x})/(5(e^x-e^{-2x))^{4/5}}

What is the first derivative of (e^x-e^{-2x}^{1/5}) ?

The first derivative of (e^x-e^{-2x}^{1/5}) is (e^x+2e^{-2x})/(5(e^x-e^{-2x))^{4/5}}

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Popular >

\frac{d}{d x} ((e^{x} - e^{- 2 x})^{\frac{1}{5}})

\frac{e ^{x} + 2 e ^{- 2 x}}{5 ( e ^{x} - e ^{- 2 x} ) ^{\frac{4}{5}}}

Solution steps

\frac{d}{d x} ((e^{x} - e^{- 2 x})^{\frac{1}{5}})

Apply the chain rule:

\frac{1}{5 ( e ^{x} - e ^{- 2 x} ) ^{\frac{4}{5}}} \frac{d}{d x} (e^{x} - e^{- 2 x})

= \frac{1}{5 ( e ^{x} - e ^{- 2 x} ) ^{\frac{4}{5}}} \frac{d}{d x} (e^{x} - e^{- 2 x})

\frac{d}{d x} (e^{x} - e^{- 2 x}) = e^{x} + 2 e^{- 2 x}

= \frac{1}{5 ( e ^{x} - e ^{- 2 x} ) ^{\frac{4}{5}}} (e^{x} + 2 e^{- 2 x})

Simplify

\frac{1}{5 ( e ^{x} - e ^{- 2 x} ) ^{\frac{4}{5}}} (e^{x} + 2 e^{- 2 x}) : \frac{e ^{x} + 2 e ^{- 2 x}}{5 ( e ^{x} - e ^{- 2 x} ) ^{\frac{4}{5}}}

= \frac{e ^{x} + 2 e ^{- 2 x}}{5 ( e ^{x} - e ^{- 2 x} ) ^{\frac{4}{5}}}

\frac{d}{d x} (\frac{( 3 x - 1 )}{2 x + 1})

\int 4 cos (x) d x

f (x) = x^{\frac{3}{2}} + \frac{1}{x ^{\frac{5}{2}}}

\frac{d}{d x} (x^{2} e^{7 x})

\int \frac{( e ^{t} + 2 e ^{2 t} )}{e ^{3 t}} d t

What is the derivative of (e^x-e^{-2x}^{1/5}) ?
The derivative of (e^x-e^{-2x}^{1/5}) is (e^x+2e^{-2x})/(5(e^x-e^{-2x))^{4/5}}
What is the first derivative of (e^x-e^{-2x}^{1/5}) ?
The first derivative of (e^x-e^{-2x}^{1/5}) is (e^x+2e^{-2x})/(5(e^x-e^{-2x))^{4/5}}