What is the derivative of f(x)=cos(x)-9x ?

The derivative of f(x)=cos(x)-9x is -sin(x)-9

What is the first derivative of f(x)=cos(x)-9x ?

The first derivative of f(x)=cos(x)-9x is -sin(x)-9

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derivative of

f (x) = cos (x) - 9 x

- sin (x) - 9

Solution steps

\frac{d}{d x} (cos (x) - 9 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (cos (x)) - \frac{d}{d x} (9 x)

\frac{d}{d x} (cos (x)) = - sin (x)

\frac{d}{d x} (9 x) = 9

= - sin (x) - 9

\frac{d}{d x} (sin (cos (sin (x))))

\frac{\partial}{\partial x} (\frac{c}{x})

\int 3 x^{2} - cos (x) + C d x

\int \frac{x}{202 1 ^{x}} d x

\frac{d}{d x} (x^{11} h (x))

What is the derivative of f(x)=cos(x)-9x ?
The derivative of f(x)=cos(x)-9x is -sin(x)-9
What is the first derivative of f(x)=cos(x)-9x ?
The first derivative of f(x)=cos(x)-9x is -sin(x)-9