What is the tangent of f(x)= 8/x ?

The tangent of f(x)= 8/x is y=-8/(a_{0)^2}x+(16)/(a_{0)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)= 8/x

tangent of

f (x) = \frac{8}{x}

y = - \frac{8}{a _{0}^{2}} x + \frac{16}{a _{0}}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, \frac{8}{a _{0}})

Find the slope of

f (x) = \frac{8}{x} : \frac{df ( x )}{d x} = - \frac{8}{x ^{2}}

Compute the slope of

f (x) = \frac{8}{x}

x = a_{0} : m = - \frac{8}{a _{0}^{2}}

Find the line with slope m=

- \frac{8}{a _{0}^{2}}

and passing through

(a_{0}, \frac{8}{a _{0}}) : y = - \frac{8}{a _{0}^{2}} x + \frac{16}{a _{0}}

y = - \frac{8}{a _{0}^{2}} x + \frac{16}{a _{0}}

x \to - π lim ((x + π) cot (x))

\int sin^{7} (y) d y

\int \frac{3}{35} x^{2} d x

y^{^{'''}} + 2 y^{^{''}} - 13 y^{^{'}} + 10 y = 0

y^{^{''}} + 2 y^{^{'}} + 4 y = 0

What is the tangent of f(x)= 8/x ?
The tangent of f(x)= 8/x is y=-8/(a_{0)^2}x+(16)/(a_{0)}