What is the derivative of x^2ln(7x) ?

The derivative of x^2ln(7x) is 2xln(7x)+x

What is the first derivative of x^2ln(7x) ?

The first derivative of x^2ln(7x) is 2xln(7x)+x

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derivative of

x^{2} ln (7 x)

2 x ln (7 x) + x

Solution steps

\frac{d}{d x} (x^{2} ln (7 x))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{2}, g = ln (7 x)

= \frac{d}{d x} (x^{2}) ln (7 x) + \frac{d}{d x} (ln (7 x)) x^{2}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (ln (7 x)) = \frac{1}{x}

= 2 x ln (7 x) + \frac{1}{x} x^{2}

\frac{1}{x} x^{2} = x

= 2 x ln (7 x) + x

f (x) = x + 1, at x = 8

\int (x^{2} + 2 x)^{3} d x

t sin (t)

\frac{d}{d x} (\frac{2}{( 3 x ^{2} + 7 ) ^{2}})

\frac{\partial}{\partial x} (e^{x y} sin (z))

What is the derivative of x^2ln(7x) ?
The derivative of x^2ln(7x) is 2xln(7x)+x
What is the first derivative of x^2ln(7x) ?
The first derivative of x^2ln(7x) is 2xln(7x)+x