What is the integral of 7/(2x^{9/4)} ?

The integral of 7/(2x^{9/4)} is -(14)/(5x^{5/4)}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 7/(2x^{9/4)}

\int \frac{7}{2 x ^{\frac{9}{4}}} d x

- \frac{14}{5 x ^{\frac{5}{4}}} + C

Solution steps

\int \frac{7}{2 x ^{\frac{9}{4}}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{7}{2} \cdot \int \frac{1}{x ^{\frac{9}{4}}} d x

Apply the Power Rule

: - \frac{4}{5 x ^{\frac{5}{4}}}

= \frac{7}{2} (- \frac{4}{5 x ^{\frac{5}{4}}})

Simplify

\frac{7}{2} (- \frac{4}{5 x ^{\frac{5}{4}}}) : - \frac{14}{5 x ^{\frac{5}{4}}}

= - \frac{14}{5 x ^{\frac{5}{4}}}

Add a constant to the solution

= - \frac{14}{5 x ^{\frac{5}{4}}} + C

y^{^{''}} - 8 y^{^{'}} + 16 y = t^{- 9} e^{4 t}

n \to \infty lim (\frac{n}{6})

\frac{\partial}{\partial y} (y e^{x y} + 2 x - 1)

\frac{\partial}{\partial x} (8 y - 4 x)

What is the integral of 7/(2x^{9/4)} ?
The integral of 7/(2x^{9/4)} is -(14)/(5x^{5/4)}+C