What is the slope ofintercept (-7,-3),(-5,-8) ?

The slope ofintercept (-7,-3),(-5,-8) is y=-5/2 x-41/2

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slope ofintercept (-7,-3),(-5,-8)

slope intercept

(- 7, - 3), (- 5, - 8)

y = - \frac{5}{2} x - \frac{41}{2}

Solution steps

Compute the slope

(- 7, - 3), (- 5, - 8) : m = - \frac{5}{2}

Compute the

y

intercept:

b = - \frac{41}{2}

Construct the line equation

y = mx + b

where

m = - \frac{5}{2}

and

b = - \frac{41}{2}

y = - \frac{5}{2} x - \frac{41}{2}

\int sin^{4} (θ) cos^{2} (θ) d θ

\int_{1}^{7} x^{2} ln (x) d x

2 - x^{2}

\frac{d}{d t} (a cos (w (t) t) + b sin (w (t) t))

\frac{d}{d x} (ln (\frac{x ^{3}}{x ^{5} + 1}))

What is the slope ofintercept (-7,-3),(-5,-8) ?
The slope ofintercept (-7,-3),(-5,-8) is y=-5/2 x-41/2