What is the derivative of 1+csc(x) ?

The derivative of 1+csc(x) is -cot(x)csc(x)

What is the first derivative of 1+csc(x) ?

The first derivative of 1+csc(x) is -cot(x)csc(x)

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\frac{d}{d x} (1 + csc (x))

- cot (x) csc (x)

Solution steps

\frac{d}{d x} (1 + csc (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) + \frac{d}{d x} (csc (x))

\frac{d}{d x} (1) = 0

\frac{d}{d x} (csc (x)) = - cot (x) csc (x)

= 0 - cot (x) csc (x)

Simplify

= - cot (x) csc (x)

x \to - \infty lim (- x e^{x})

y = x^{2} - 4 x, y = 2 x - x^{2}

f (x) = x + \frac{1}{x}, at x = 3

\frac{4 x ^{2} + 1}{x ^{2} + 5}

\frac{d}{d x} (x^{4} - 6 x^{2} + 4)

What is the derivative of 1+csc(x) ?
The derivative of 1+csc(x) is -cot(x)csc(x)
What is the first derivative of 1+csc(x) ?
The first derivative of 1+csc(x) is -cot(x)csc(x)