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Popular >

integral of 1/(y-4)

Solution

\int \frac{1}{y - 4} d y

Solution

ln ∣ y - 4 ∣ + C

Solution steps

\int \frac{1}{y - 4} d y

Apply u-substitution

: \int \frac{1}{u} d u

= \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= ln ∣ u ∣

Substitute back

u = y - 4

= ln ∣ y - 4 ∣

Add a constant to the solution

= ln ∣ y - 4 ∣ + C

Popular Examples

4y^{''}-40y^'+96y=5sin(2x)

4 y^{^{''}} - 40 y^{^{'}} + 96 y = 5 sin (2 x)

integral from 1 to e^2 of x^3ln(x)

\int_{1}^{e^{2}} x^{3} ln (x) d x

join x+(1/x)join

x + (\frac{1}{x})

derivative of f(x)=|x^2-4|derivative of

f (x) = x^{2} - 4

derivative of 1/(2-cos(pix))

\frac{d}{d x} (\frac{1}{2 - cos ( π ) x})

Frequently Asked Questions (FAQ)

What is the integral of 1/(y-4) ?
The integral of 1/(y-4) is ln|y-4|+C