What is the solution for -2y^2dy=y^3vdv ?

The solution for -2y^2dy=y^3vdv is v=sqrt(-4ln(y)+c_{1)},v=-sqrt(-4ln(y)+c_{1)}

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-2y^2dy=y^3vdv

- 2 y^{2} d y = y^{3} v d v

v = - 4 ln (y) + c_{1}, v = - - 4 ln (y) + c_{1}

Solution steps

- 2 y^{2} d y = y^{3} v d v

Solve separable ODE:

v = - 4 ln (y) + c_{1}, v = - - 4 ln (y) + c_{1}

v = - 4 ln (y) + c_{1}, v = - - 4 ln (y) + c_{1}

x \to 4 lim ((5 x + 7)^{4})

\int \frac{4 x ^{3} + 2 x ^{2} + 8}{( x ^{2} + 4 ) ^{2}} d x

\frac{d}{d x} (\frac{( ln ( x ) ) ^{2}}{e ^{x}})

f (x) = 8 sin (2 x)

\int \frac{1}{b - a} d x

What is the solution for -2y^2dy=y^3vdv ?
The solution for -2y^2dy=y^3vdv is v=sqrt(-4ln(y)+c_{1)},v=-sqrt(-4ln(y)+c_{1)}