What is the derivative of ln(x^3+1) ?

The derivative of ln(x^3+1) is (3x^2)/(x^3+1)

What is the first derivative of ln(x^3+1) ?

The first derivative of ln(x^3+1) is (3x^2)/(x^3+1)

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derivative of

ln (x^{3} + 1)

\frac{3 x ^{2}}{x ^{3} + 1}

Solution steps

\frac{d}{d x} (ln (x^{3} + 1))

Apply the chain rule:

\frac{1}{x ^{3} + 1} \frac{d}{d x} (x^{3} + 1)

= \frac{1}{x ^{3} + 1} \frac{d}{d x} (x^{3} + 1)

\frac{d}{d x} (x^{3} + 1) = 3 x^{2}

= \frac{1}{x ^{3} + 1} \cdot 3 x^{2}

Simplify

\frac{1}{x ^{3} + 1} \cdot 3 x^{2} : \frac{3 x ^{2}}{x ^{3} + 1}

= \frac{3 x ^{2}}{x ^{3} + 1}

\int 0.5 x^{2} d x

x \to \infty lim (- 1^{x})

\frac{d}{d x} (arccos (e^{x}))

x \to - 1 lim (- x^{2})

ln (2 t)

What is the derivative of ln(x^3+1) ?
The derivative of ln(x^3+1) is (3x^2)/(x^3+1)
What is the first derivative of ln(x^3+1) ?
The first derivative of ln(x^3+1) is (3x^2)/(x^3+1)