What is the derivative of ln(-3x+2) ?

The derivative of ln(-3x+2) is -3/(-3x+2)

What is the first derivative of ln(-3x+2) ?

The first derivative of ln(-3x+2) is -3/(-3x+2)

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\frac{d}{d x} (ln (- 3 x + 2))

- \frac{3}{- 3 x + 2}

Solution steps

\frac{d}{d x} (ln (- 3 x + 2))

Apply the chain rule:

\frac{1}{- 3 x + 2} \frac{d}{d x} (- 3 x + 2)

= \frac{1}{- 3 x + 2} \frac{d}{d x} (- 3 x + 2)

\frac{d}{d x} (- 3 x + 2) = - 3

= \frac{1}{- 3 x + 2} (- 3)

Simplify

\frac{1}{- 3 x + 2} (- 3) : - \frac{3}{- 3 x + 2}

= - \frac{3}{- 3 x + 2}

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ln (cos^{x} (x))

\int \frac{( 2 x + 3 )}{x ^{3} + x ^{2} - 2 x} d x

What is the derivative of ln(-3x+2) ?
The derivative of ln(-3x+2) is -3/(-3x+2)
What is the first derivative of ln(-3x+2) ?
The first derivative of ln(-3x+2) is -3/(-3x+2)