What is inverse oflaplace 7/(s^2+49) ?

The answer to inverse oflaplace 7/(s^2+49) is sin(7t)

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inverse oflaplace 7/(s^2+49)

inverse laplace

\frac{7}{s ^{2} + 49}

sin (7 t)

Solution steps

L^{- 1} {\frac{7}{s ^{2} + 49}}

Use Inverse Laplace Transform table:

L^{- 1} {\frac{a}{s ^{2} + a ^{2}}} = sin (a t)

L^{- 1} {\frac{7}{s ^{2} + 7 ^{2}}} = sin (7 t)

= sin (7 t)

\frac{d}{d x} (arcsec (3 x))

\int 5 x^{2} - \frac{4}{x} + a d x

\int (1 - x)^{2} d x

\int (5 z^{2} - 3)^{3} z d z

\frac{\partial}{\partial x} (e^{7 y} sin (- 7 x))

What is inverse oflaplace 7/(s^2+49) ?
The answer to inverse oflaplace 7/(s^2+49) is sin(7t)