What is the solution for derivative of [f(x^2)]=x^5 ?

The solution for derivative of [f(x^2)]=x^5 is f(x)=(x^4)/6+(c_{1})/(x^2)

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derivative of [f(x^2)]=x^5

\frac{d}{d x} [f (x^{2})] = x^{5}

f (x) = \frac{x ^{4}}{6} + \frac{c _{1}}{x ^{2}}

Solution steps

\frac{d}{d x} (f (x) (x^{2})) = x^{5}

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

f (x) x^{2} = \int x^{5} d x

\int x^{5} d x = \frac{x ^{6}}{6} + c_{1}

f (x) x^{2} = \frac{x ^{6}}{6} + c_{1}

Isolate

f (x) : f (x) = \frac{x ^{4}}{6} + \frac{c _{1}}{x ^{2}}

f (x) = \frac{x ^{4}}{6} + \frac{c _{1}}{x ^{2}}

\frac{\partial}{\partial x} (x^{2} + 2 x y + 3 y^{4})

\int \frac{1}{x x + 1} d x

y = ln (\frac{4}{x ^{3}})

\frac{\partial}{\partial x} (x cos (\frac{1}{x ^{2} + y ^{2}}))

\frac{\partial}{\partial x} (e^{(x - y)})

What is the solution for derivative of [f(x^2)]=x^5 ?
The solution for derivative of [f(x^2)]=x^5 is f(x)=(x^4)/6+(c_{1})/(x^2)