What is (\partial)/(\partial x)(x+ycos(y)) ?

The answer to (\partial)/(\partial x)(x+ycos(y)) is 1

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(\partial)/(\partial x)(x+ycos(y))

\frac{\partial}{\partial x} (x + y cos (y))

1

Solution steps

\frac{\partial}{\partial x} (x + y cos (y))

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x) + \frac{\partial}{\partial x} (y cos (y))

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (y cos (y)) = 0

= 1 + 0

Simplify

= 1

\int_{0}^{π} 2 x^{2} sin (\frac{1}{2} x) d x

\frac{4 x ^{2} + 2 x + 2}{x}

\frac{d}{d x} (x^{2} - 7 x + 2)

\frac{d}{d x} (\frac{( x + 1 - 1 )}{x})

\frac{d}{d x} (3 e^{x} + 5 x^{2})

What is (\partial)/(\partial x)(x+ycos(y)) ?
The answer to (\partial)/(\partial x)(x+ycos(y)) is 1