What is the derivative of-cos(2x)-2sin(2x)(1-x) ?

The derivative of-cos(2x)-2sin(2x)(1-x) is 4xcos(2x)+4sin(2x)-4cos(2x)

What is the first derivative of-cos(2x)-2sin(2x)(1-x) ?

The first derivative of-cos(2x)-2sin(2x)(1-x) is 4xcos(2x)+4sin(2x)-4cos(2x)

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derivative of

- cos (2 x) - 2 sin (2 x) (1 - x)

4 x cos (2 x) + 4 sin (2 x) - 4 cos (2 x)

Solution steps

\frac{d}{d x} (- cos (2 x) - 2 sin (2 x) (1 - x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (cos (2 x)) - \frac{d}{d x} (2 sin (2 x) (1 - x))

\frac{d}{d x} (cos (2 x)) = - sin (2 x) \cdot 2

\frac{d}{d x} (2 sin (2 x) (1 - x)) = 2 (2 cos (2 x) (1 - x) - sin (2 x))

= - (- sin (2 x) \cdot 2) - 2 (2 cos (2 x) (1 - x) - sin (2 x))

Simplify

- (- sin (2 x) \cdot 2) - 2 (2 cos (2 x) (1 - x) - sin (2 x)) : 4 x cos (2 x) + 4 sin (2 x) - 4 cos (2 x)

= 4 x cos (2 x) + 4 sin (2 x) - 4 cos (2 x)

cos (sin (tan (7 x)))

1, 8, [- 0.5 x + 6], x + 2

\frac{d}{d x} (\frac{3 ( 1 - sin ( x ) )}{2 cos ( x )})

\frac{d}{d x} ((7 x^{2} + 6 x)^{7})

\int_{2}^{3} e^{x} d x

What is the derivative of-cos(2x)-2sin(2x)(1-x) ?
The derivative of-cos(2x)-2sin(2x)(1-x) is 4xcos(2x)+4sin(2x)-4cos(2x)
What is the first derivative of-cos(2x)-2sin(2x)(1-x) ?
The first derivative of-cos(2x)-2sin(2x)(1-x) is 4xcos(2x)+4sin(2x)-4cos(2x)